Question

Solve the following quadratic equation by completing the square method. (x×x)+2x-5=0

Answer 1

Answer:

$\large{\bold{x=-1+\sqrt{6}\;\;,-1-\sqrt{6}}}$

Step-by-step explanation:

$x^2+2x-5=0\\\\=>x^2+2(x)(1)+(1)^2=5+1\\\\=>(x+1)^2=6\\\\=>x+1=|\sqrt{6}\;|\;\\\\=>x+1=\sqrt{6}\\=>x=-1+\sqrt{6}\\\\\\=>x+1=-\sqrt{6}\\=>x=-1-\sqrt{6}\\\\\\\\FORMULA\\\\(a+b)^2=a^2+2ab+b^2$

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