Question

solve the following quadratic equation by completing the square x square minus 4 root 2 X + 6 is equal to zero​

Answer 1

Solution:

Given Quadratic equation:

x²-4√2x+6=0

=> x²-4√2x = -6

=> x²-2*x*2√2 = -6

=> x²-2*x*2√2+(2√2)²=-6+(2√2)²

=> (x-2√2)² = -6 + 8

=> (x-2√2)² = 2

=> x-2√2 = ±2

=> x = 2√2 ± 2

=> x = 2(√2±1)

Therefore,

x = 2(√2+1) or x = 2(√2-1)

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Answer 2

Answer:

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Step-by-step explanation:

x²-4√2x+6=0

=> x²-4√2x = -6

=> x²-2*x*2√2 = -6

=> x²-2*x*2√2+(2√2)²=-6+(2√2)²

=> (x-2√2)² = -6 + 8

=> (x-2√2)² = 2

=> x-2√2 = ±2

=> x = 2√2 ± 2

=> x = 2(√2±1)

Therefore,

x = 2(√2+1) or x = 2(√2-1)

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