solve the following quadratic equation by facterization
Answers
Answered by
1
Step-by-step explanation:
I think some mistake in your question, because given equation is a linear not quadratic.
From my opinion, your question is √(2) x² - 3x - 2√2
So, I solve above equation
√(2) x² - 3x -2√2 = 0
applying sridharacharya formula in equation,
x = {-b±√(b²-4ac)}/2a
And here, a=√2, b=-3, c=-2√2
[because general quadratic equation is ax² + bx +c =0]
Now put the values of a,b and c in formula;
x={3±√(9+16)}/2√2
= {3±5}/2√2
x=+2√2 and x=-1/√2
I hope this will help you
Similar questions