Question

solve the following quadratic equation by factorisation 1) 3x^2 -2 √6x +2 =0​

Answer 1

Step-by-step explanation:

3x² - 2√6x + 2 = 0

3x² - √6x - √6x + 2 = 0

√3x(√3x - √2) - √2(√3x - √2) = 0

(√3x - √2) (√3x - √2) = 0

(√3x + √2)² = 0

▬▬▬▬▬▬▬▬

USING IDENTITY → (a - b)² = a² - 2ab + b²

3x² - 2√6x + 2 = 0

(√3x)² - 2*√3*√2 + (√2)² = 0

(√3x + √2)² = 0

▬▬▬▬▬▬▬▬