Question

Solve the following quadratic equation by factorisation method;X^2+2x-120=0​

Answer 1

x²+2x-120

=x²+12x-10x-120

=x(x+12)-10(x+12)

=(x+12) (x-10)

Answer 2

Given quadratic equation is-

X² + 2x -120 = 0

Let us factorise it!

$\mathsf{{x}^{2}+2x-120 = 0}$

$\mathsf{{x}^{2}+12x -10x -120 = 0}$

$\mathsf{x(x+12) - 10(x+12) = 0}$

$\mathsf{(x+12)(x-10) = 0}$

Hence,

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