Question

solve the following quadratic equation by factorisation method
q2- 2(7q+16) = 0​

Answer 1

Answer:

q^2-2(7q+16)=0

or q^2-14q-32=0

or. q^2+2q-16q-32=0

or q(q+2)-16(q+2)=0

or. (q+2)(q-16)=0

So,q=-2 or +16.

Answer 2

Answer:

q = -2 and q = 16

Step-by-step explanation:

Given Quadratic Equation :

                         $q^2-2(7q+16)=0$

We have to solve the quadratic equation by factorization method.

Simplifying and converting the following equation into standard form of quadratic equation

                       $q^2-2(7q+16)=0$

                          $q^2-14q-32=0$

since -14q can be written as -16q+2q

so                   $q^2-16q+2q-32=0$

                     $(q^2-16q)+(2q-32)=0$

take common q from first bracket and 2 from second bracket.

                    $q(q-16)+2(q-16)=0$

taking common (q-16) from the equation we get

                             $(q-16)(q+2)=0$

Here either (q-16) = 0 or (q+2)=0

so we get q = 16 or q = -2 which are the two zeros of the given quadratic equation.

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