Question

Solve the following quadratic equation by factorisation methoa. 2x²+√5x-15=0

Answer 1

Answer:

Please check the attached image.

Answer 2

★ sOLUTIOn ★

$\implies 2x^2+\sqrt5x-15=0\\ \implies 2x^2+3\sqrt5x-2\sqrt5x+15=0\\ \implies x(2x+3\sqrt5)-\sqrt5(2x+3\sqrt5)=0\\ \implies(x-\sqrt5) (2x+3\sqrt5)=0\\ \implies 2x-3\sqrt5=0, x-\sqrt5=0\\ \implies x=\frac{-3\sqrt5}{2}, x=\sqrt5$

$\rule{150}2$

Hence,

$\implies x=\frac{-3\sqrt5}{2}\\ \implies x=\sqrt5$