Question

solve the following quadratic equation by factorisation 2/3x2-1/3x-1=0​

Answer 1

Answer:

values of x are 3/2 and -1

Answer 2

The value of x would be

$x=1\pm \dfrac{1}{\sqrt{3}}$

Step-by-step explanation:

Since we have given that

$\dfrac{2}{3x^2}-\dfrac{1}{3x-1}=0$

We need to solve the quadratic equation:

So, it becomes,

$\dfrac{2(3x-1)-3x^2}{3x^2(3x-1)}=0\\\\\dfrac{6x-2-3x^2}{9x^3-3x^2}=0\\\\3x^2-6x+2=0\\\\x=1\pm \dfrac{1}{\sqrt{3}}$

Hence, the value of x would be

$x=1\pm \dfrac{1}{\sqrt{3}}$