Question

solve the following quadratic equation by factorisation 3 x square - 14 x minus 5 is equal to zero​

Answer 1

Answer:

$= > 3 {x}^{2} - 14x - 5 = 0 \\ \\ = > 3 {x}^{2} - (15 - 1)x - 5 = 0\\ \\ = > 3 {x}^{2} - 15x + x - 5 = 0\\ \\ = > 3x(x - 5) + 1(x - 5) = 0 \\ \\ = > (x - 5)(3x + 1) = 0 \\ \\ = > x - 5 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 3x + 1 = 0 \\ \\ = > x = 5 \: \: \: \: \: \: x = - \frac{1}{3}$

Answer 2

$\huge\bf {3x}^{2} - 14x - 5 = 0 \\ \\ \leadsto \: \: \: \: \: \: \: \: \: \rm {3x}^{2} - 15x + x - 5 = 0 \\ \leadsto \: \: \: \: \rm 3x(x - 5) + 1(x - 5) = 0 \\ \leadsto \: \: \: \: \: \: \: \: \: \: \: \: \: \: \rm(3x + 1)(x - 5) = 0 \\ \\ \leadsto \: \: \: \: \sf \: \: \: \: x = \bigg( \red{ \frac{ - 1}{3}} \bigg) \: \: \: \: \: or \: \: \: \: \: \red5$