Question

solve the following quadratic equation by factorisation solve the following quadratic equation by factorisation method 12x^2-x-1=0 been fast pls​

Answer 1

Answer:

12^2-x-1 = 0

12*12-x-1 = 0

144-x = 1

x = 144+1

x = 145

Step-by-step explanation:

Answer 2

⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀☆ GIVEN QUADRATIC EQUATION : 12x² - x - 1 = 0

$\qquad \dashrightarrow \sf 12x^2 - x - 1 = 0 \:\:$

$\qquad \dashrightarrow \sf 12x^2 + 3x - 4x - 1 = 0 \:\:$

$\qquad \dashrightarrow \sf 3x (4x + 1 ) - 1( 4x + 1 ) = 0 \:\:$

$\qquad \dashrightarrow \sf (3x - 1 ) ( 4x + 1 ) = 0 \:\:$

$\qquad \dashrightarrow \sf x \:\:=\:\: \dfrac{\:\:1\:\:}{\:\:3\:\:} \:\:or\:x \:\:=\:\: \dfrac{\:\:-1\:\:}{\:\:4\:\:} \:\:$

$\qquad \therefore \pmb{\underline{\purple{\: x \:\:=\:\: \dfrac{\:\:1\:\:}{\:\:3\:\:} \:\:or\:\:\: \dfrac{\:\:-1\:\:}{\:\:4\:\:} \:\: }} }\:\:\bigstar$

$\therefore \underline {\sf Hence, \:The\:zeroes \:of\:given \:Equation \:are \: \bf \dfrac{\:\:1\:\:}{\:\:3\:\:} \:\:and\:\:\: \dfrac{\:\:-1\:\:}{\:\:4\:\:} }$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀⠀$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

$\qquad \qquad \boxed {\begin{array}{cc} \bf{\underline {\bigstar\:\: For \: a \:Quadratic \:Polynomial \::}}\\\\ \sf{ Whose \:\:zeroes \:\:are\:\:\alpha \:\&\;\: \beta\:\:} \\\\ 1)\:\: \alpha + \beta \: =\:\dfrac{-b}{a} \quad \bigg\lgroup \bf Sum\:of\;Zeroes \bigg\rgroup \\\\ 2)\:\: \alpha \times \beta \: =\:\dfrac{c}{a} \quad \bigg\lgroup \bf Product \:of\;Zeroes \bigg\rgroup \\\\ \end{array}}$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━