Solve the following quadratic equation by factorisation method
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(2y+1)(y+13)
Step-by-step explanation:
Solve the following quadratic equation by factorization
i] 2y²+27y+13=0
2y²+27y+13=0 {2y²×13=26y²}
=2y²+1y+26y+13=0{1y×26y=26y²}
{1y+26y=27y}
=y(2y+1)+13(2y+1)
=(2y+1)(y+13)
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