Question

solve the following quadratic equation by factorisation: x^2-5x+6=0​

Answer 1

Answer:

$\mathrm{x^2-5x+6=0\quad :\quad x=3,\:x=2}$

Step-by-step explanation:

$\mathrm{x^2-5x+6=0}$

$\mathrm{x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:1\times \:6}}{2\times \:1}}$

$\mathrm{x_{1,\:2}=\frac{-\left(-5\right)\pm \:1}{2\cdot \:1}}$

$\mathrm{Separate\:the\:solutions}$

$\mathrm{x_1=\frac{-\left(-5\right)+1}{2\cdot \:1},\:x_2=\frac{-\left(-5\right)-1}{2\cdot \:1}}$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$\mathrm{x=3,\:x=2}$