solve the following quadratic equation by factorisation x2-3√3x+6=0
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Step-by-step explanation:
x²-3√3x+6=0
x²-√3x-2√3x+6=0
x(x-√3)-2(x-√3)=0
(x-√3) (x-2)=0
x=√3 or x=2
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hope this will help
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