Question

Solve the following quadratic equation by factorisation. x²-15x + 54 = 0​

Answer 1

$given \: {x}^{2} - 15x + 54 = 0 \\ {x }^{2} - 6x - 9x + 54 = 0 \\ x(x - 6) - 9(x - 6) = 0 \\ (x - 6)(x - 9) = 0$

x= 6,9

⇒(x−9)(x−6)=0

⇒x=9,6

Answer 2

Answer:

X² – 15x + 54 = 0

⇒ x² - 9x - 6x + 54 = 0

⇒ x (x - 9) - 6 (x - 9) = 0

⇒ (x - 6) (x - 9) = 0

⇒ (x - 6) = 0 or (x - 9) = 0

⇒ x = 6 or x = 9

So, 6 and 9 are the roots of the given quadratic equation.