Question

Solve the following quadratic equation by factorisation x2+3x-28=0​

Answer 1

Step-by-step explanation:

x^2+3x-28 = x^2+7x-4x-28

=x (x+7)-4 (x+7)

=(x+7) (x-4)

x+7=0

x=-7

ALSO...

x-4=0

x=4