solve the following Quadratic
Equation by factorization method
x²-3√3x+6=0
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Answer:
x2-3√3×+6=0
Sum = - 3 3√, product=6;
x2 - 2√ 3x - √3x + 6 =0
x (x -2 √3) - √3 (x- 2√ 3) = 0
(x - 2√3) (x - √3)=0
x= 2 √ or √3
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