Question

solve the following quadratic equation by factorization method x^-17x+60=0​

Answer 1

${\red{\underline{\underline{\bold{Given:-}}}}}$

• ${x}^{2} -17x +60 = 0$

${\blue{\underline{\underline{\bold{To\:Find:-}}}}}$

• The value of x

${\green{\underline{\underline{\bold{Solution:-}}}}}$

${x}^{2} - 17x + 60 = 0 \\ \\</p><p></p><p>\implies {x}^{2} -12x-5x + 60 = 0 \\ \\</p><p></p><p>\implies x(x-12) - 5(x-12) = 0 \\ \\</p><p></p><p>\implies (x-12) (x-5) \\ \\</p><p></p><p>x-12 = 0 \: (or) \: x-5 = 0 \\ \\</p><p></p><p>x = 12 \: (or) x = 5$

_________________

${\pink{\underline{\underline{\bold{Answer\:Verification:-}}}}}$

Case 1:-

Substitute x = 12 in ${x}^{2} -17x +60 = 0$

$\implies {12}^{2} - 17(12) + 60 = 0 \\ \\</p><p></p><p>\implies 144 - 204 +60 = 0 \\ \\</p><p></p><p>\implies0 = 0$

L.H.S = R.H.S

Case 2:-

Substitute x = 5 in ${x}^{2} -17x +60 = 0$

$\implies {5}^{2} - 17(5) + 60 = 0 \\ \\</p><p></p><p>\implies 25 - 85 +60 = 0 \\ \\</p><p></p><p>\implies0 = 0$

L.H.S = R.H.S

Hence, verified