solve the following quadratic equation by factorization method 7y2-6y-1=0
Answers
Answered by
1
Answer:
7y² - 6y - 1
= 7y² - 7y + y - 1
= 7y(y-1) + 1(y-1)
= (y-1)(7y+1)
Answered by
2
Answer:
7y²-6y-1 = 0
by middle term splitting
7y²-7y+y-1 = 0
7y(y-1)+1(y-1) = 0
(7y+1)(y-1) = 0
one of them must be zero.
y-1 = 0
y = 1
7y+1 = 0
7y = -1
y = -1/7
y = 1, -1/7 (answer)
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