Question

Solve the following quadratic equation by factorization method : 
3x² -2x - 8 = 0 *​

Answer 1

Answer:

$3 {x}^{2} - 2x - 8 = 0 \\ \\ = > 3 {x}^{2} - (6 - 4)x - 8 = 0 \\ \\ = > 3 {x}^{2} - 6x + 4x - 8 = 0 \\ \\ = > 3x(x - 2) + 4(x - 2) = 0 \\ \\ = > (3x + 4)(x - 2) = 0 \\ \\ either \: 3x + 4 = 0 \\ \\ = > x = \frac{ - 4}{3} \\ \\ or \: x - 2 = 0 \\ \\ = >x = 2$

# keep smiling ☺

Answer 2

$\huge\underline\color{gold}{AnSWeR}$

$3 {x}^{2} - 2x - 8 = 0$

$3 {x}^{2} - 6x + 4x - 8 = 0$

$3x( x - 2) + 4(x - 2) = 0$

$(x - 2)(3x + 4) = 0$

$x - 2 = 0 \: \: \: \: \: \: 3x + 4 = 0$

$x = 2 \: \: \: OR \: \: \: x = \frac{ - 4}{3}$