Question

Solve the following quadratic equation by factorization method. x square +x - 20=0
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Answer 1

Step-by-step explanation:

x^2+x-20=0

x^2+5x-4x-20 =0 (using middle term split)

x(x+5)-4(x+5)=0

(x+5)(x-4)=0

There are two answers possible in quadratic equation.

if

(x+5)=0/(x-4)

x+5=0

x=-5

if

x-4=0/(x+5)

x-4=0

x=4

Answer 2

Answer:

4 and -5

Step-by-step explanation:

${x}^{2} + x - 20 = 0 \\ = > \: {x}^{2} + 5x - 4x - 20 = 0 \\ = > x(x + 5) - 4(x + 5) = 0 \\ = > (x - 4)(x + 5) = 0 \\ = > (x - 4) = 0 \: or \: (x + 5) = 0 \\ = > x = 4 \: or \: x = - 5$

So, 4 and -5 are the roots of the given quadratic equation