Question

solve the following quadratic equation by factorization method​

Answer 1

Step-by-step explanation:

Question:-

Solve it

$\\ \tt{:}\twoheadrightarrow \dfrac{1}{x+2}=\dfrac{1}{x^2}$

SOLUTION:-

$\\ \tt{:}\twoheadrightarrow \frac{1}{x + 2} = \frac{1}{ {x}^{2} } \\ \bf \bigstar\: using \: cross \: multiplication\\ \\ \tt{:}\twoheadrightarrow {x}^{2} = x + 2 \\ \\ \tt{:}\twoheadrightarrow {x}^{2} - x - 2 = 0 \\ \\ \tt{:}\twoheadrightarrow {x}^{2} - 2x + x - 2 = 0 \\ \\ \tt{:}\twoheadrightarrow x(x - 2) + 1(x - 2) = 0 \\ \\ \tt{:}\twoheadrightarrow (x - 2)(x + 1) = 0 \\ \\ \tt{:}\twoheadrightarrow (x - 2) = 0 \:or \: (x + 1) = 0 \\ \\ \tt{:}\twoheadrightarrow x = 2 \: or \: x = - 1$