Question

Solve the following quadratic equation by factorization method

x²- 5ix-6= 0

Answer 1

$\boxed{Question-}$Solve the following quadratic equation by factorization method

x²- 5ix-6= 0

$\huge\bold{Solution}$

➡️The given equation is

$x {}^{2} - 5ix - 6 = 0 \\x {}^{2} - 5ix + 6i {}^{2} = 0 \\ x {}^{2} - 3ix - 2ix + 6i { }^{2} = 0 \\ x(x - 3i) - 2i(x - 3i) = 0 \\ (x - 3i)(x - 2i) = 0 \\ x - 3i = 0 , x - 2i = 0 \\ x = 3i , \: x = 2i$

➡️Hence , the roots of the given equation are 3i and 2i .

Answer 2

Answer:

ʜᴇʏ!!

Step-by-step explanation:

We factor by finding numbers that multiply to  

− 6  and add to  − 5 ,

of course  − 6  and  1  so  0

= x ²  −  5 x  −  6

= (  x  −  6  )  (  x  +  1  )

so  x  =  6  or  x  =  − 1 .

ᴛʜx..