Question

solve the following quadratic equation by factorization root 3 X square + 4X + 7 root 3 equal to zero​

Answer 1

Answer:

$\sqrt{3} {x}^{2} + 4x - 7 \sqrt{3} = 0$

$\sqrt{3} {x}^{2} + 7x - 3x - 7 \sqrt{3} = 0$

$\sqrt{3} x(x + \frac{7}{ \sqrt{3} } ) - 3(x + \frac{7}{ \sqrt{3} } ) = 0$

$(x + \frac{7}{ \sqrt{3} } )( \sqrt{3} x - 3) = 0$

$so \: x = - \frac{7}{ \sqrt{3} } \: \: or \: \sqrt{3} \: \: ans$

Answer 2

Answer:

$x = \frac{ - 7}{ \sqrt{3} } \: \: and \: \: \sqrt{3}$