Question

solve the following quadratic equation by factorization. x2-3√3x+6=0
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Answer 1

Answer:

x^2-3√3x+6=0

explanation: this question has some values either in part c or in part b are misplaced

the factors of 6=1 X 2 X 3

let us take 2 and 3

the difference of 2 and 3 are either 1 or -1

as 2-3=-1   and 3 -2 = 1      

the sum of 2 and 3 are either 5 or -5

i.e. -2-3=-5  and 2+3=5

so the equation either must be

x^2-5√3x+6=0 or

many other equations may be constructed

Note: this question is a good question. Please don't take it as report. Clerical mistakes may happen.