Question

solve the following quadratic equation by quadratic formula 1.)2x^2-3x-5=0
2.)5x^2+13x+8=0
3.) x^2+2√2x-6=0

​

Answer 1

Hope it helps you

Plzzz mark as Brainliest humble request

Answer 2

1) 2x² - 3x - 5 = 0

x = {-b±√(b² - 4ac)}/2a

x = {3±√(9+40)}/4

x = (3±7)/4

x = 10/4, -1

2) 5x² + 13x + 8 = 0

x = {-13±√(169-160)}/10

x = (-13±3)/10

x = -1, -16/10

3) x² + 2√2x - 6 = 0

x = {-2√2±√(8+24)}/2

x = (-2√2±4√2)/2

x = √2, -3√2

HOPE I AM CORRECT

PLEASE MARK AS BRAINLIEST

:-)