Question

solve the following quadratic equation correct two decimal places
x²=3(12-x)​

Answer 1

Step-by-step explanation:

$\huge \bold{Answer:}$

$\bold{=>x²=3(12-x)}$

$\bold{=>x² + 3x-36=0}$

$\\ \bold{ = > x = \frac{ - 3 ± 3\sqrt{17} } { 2}}$

$\bold{=>x=4.68 \ \: or \: \: x=-7.68}$

$\bold{This \: is \: the \: correct \: answer .}$