Question

Solve the following quadratic equation for x-
√2x^2 +7x +5√2=0

Answer 1

hi friend!!!

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√2x² +7x +5√2=0

=√2x²+5x+2x+5√2=0

=x(√2x+5)+√2(√2x+5)=0

=(x+√2)(√2x+5)=0

so, x+√2=0, or √2x+5=0

x=-√2. or x=-5/√2


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I hope this will help u ;)

Answer 2

p(x) = √2x² +7x +5√2 

      = √2x²+5x+2x+5√2=0

taking common terms :-

     = x(√2x+5) + √2(√2x+5) 

            ( x+√2)  (√2x+5)



x =  -√2
 x = - 5/√2

the zeros are -√2 and - 5/√2