solve the following quadratic equation for x : 4√3 x square + 5x -2√3 = 0
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4√3 × 2√3 = 8×3
Now,
4√3 x² + 5x -2√3 = 0
4√3 x² + 8x-3x -2√3 =0
4x(√3x+2)-√3(√3x+2) = 0
(4x-√3)(√3x+2) = 0
x = √3/4 or -2/√3
Now,
4√3 x² + 5x -2√3 = 0
4√3 x² + 8x-3x -2√3 =0
4x(√3x+2)-√3(√3x+2) = 0
(4x-√3)(√3x+2) = 0
x = √3/4 or -2/√3
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