solve the following quadratic equation for x: 4√3x^2+5x-2√3 =0
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X= 4/3 or -2/√3
4√3X² +5x -2√3=0
4√3x²+8x-3x-2√3=0
4x(√3x+2)-3(√3x+2)=0
(4x-3)(√3+2)=0
sox= 4/3 or -2/√3
nehaharish:
isn't it √3/ 4 . because when i factorised i took √3 out
its worng
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