Question

solve the following quadratic equation for x.4x^2 - 4a^2x+(a^2-b^2 )=0.

Answer 1

Solution :4x2+4bx−(a2−b2)=04x2+4bx−(a2−b2)=0dividing throughout by L1L1x2+bx−(a2−b2)4x2+bx−(a2−b2)4=0=0(x+b2)2−b24−(a2−b24)(x+b2)2−b24−(a2−b24)=0=0=> (x+b2)2=b2+(a2−b2)4(x+b2)2=b2+(a2−b2)4(x+b2)2=a24(x+b2)2=a24=>x+b2=>x+b2=±a2=±a2x=a−b2,−a−b2