Question

Solve the following quadratic equation for x:

4x^2 – 4a^2x + ( a^4 – b^4) = 0​

Answer 1

Answer:

Your Answer is 0.I am right.

Answer 2

Step-by-step explanation:

Let the quadratic equation be ax²+bx+c=0,

By using quadratic formula,

x={-b±✓(b²- 4ac)}/2a

Comparing with the given equation,

x= {4a²±✓(4a²)²-4*4*(a⁴-b⁴)}/2*4

= {4a²±✓16a⁴-16a⁴+16b⁴}/8

= {4a²±4b²}/8

= (a²±b²)/2

x= (a²+b²)/2, x=(a²-b²)/2