Question

Solve the following quadratic equation for x. 4x² - 4a’x +(a' - b*) = 0
=​

Answer 1

Answer:

Step-by-step explanation:

4x2-4a2x+(a4-b4)=0

a = 4, b = -4a2, c = a4−b4

D = b2−4ac

= (−4a2)2−4×4×(a4−b4)

=16a4−16a4+16b4

D = 16 b4

Therefore,by quadratic formula,we have,

x=−b±D√2a

=−(−4a2)±4b22×4

=4a2±4b28

x = a2±b22

x = a2+b22   or   x=a2−b22

 

 Hence,the roots of given quadratic equation is ,a2+b22,a2−b22

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Answer 2

Answer:

$\frac{a + - \sqrt{ {a}^{2} - a - b } }{2}$

Step-by-step explanation:

4x² - 4a'x + (a' + b') = 0

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