Question

Solve the following quadratic equation for x
4x²+4bx-(a²-b²) =0

Answer 1

4x²+4bx+(a²-b²)

= 4x²+2(b+a)x +2(b-a)x+(a+b)(a-b)

= 2x(2x+a+b)+(b-a)(2x+a+b)

= (2x+a+b)(2x+b-a)

=> x= -b-a/2 , =>x=a-b/2