solve the following quadratic equation for x: x^2-4ax-b^2+4a^2=0...soon......hw help!!!!
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x² - 4ax - b² + 4a² = 0
x² - 4ax + 4a² - b²
a = 1, b = -4a, c = 4a² - b²
D=b²-4ac
=16a² - ( 4 × 1 × 4a² - b²)
=16a² - 16a² + 4b²
= 4b²
x= - b + √D , x = - b - √D
2a 2a
x = , x = 4a + √4b² 4a - √4b²
x = 4a + 2b , x = 4a - 2b
2 2
x = 2a + b , x = 2a - b.
x² - 4ax + 4a² - b²
a = 1, b = -4a, c = 4a² - b²
D=b²-4ac
=16a² - ( 4 × 1 × 4a² - b²)
=16a² - 16a² + 4b²
= 4b²
x= - b + √D , x = - b - √D
2a 2a
x = , x = 4a + √4b² 4a - √4b²
x = 4a + 2b , x = 4a - 2b
2 2
x = 2a + b , x = 2a - b.
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