Solve the following quadratic equation for x:x2 - 4ax - b2 + 4a2 = 0 by factorisation
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x^2-4ax+4a^2-b^2=0
x^2-2*2a*x+(2a)^2-(b)^2=0
(x-2a)^2-(b)^2=0
(x-2a-b)(x-2a+b)=0
x-2a-b=0 x-2a+b=0
x=b+2a x=2a-b
Therefore, x= 2a+b or 2a-b
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