solve the following quadratic equation infactorisation method x2-2x-120=0
Answers
Answered by
1
Answer:
Find two factors of
120
which differ by
2
. The pair
12
,
10
works.
Hence:
0
=
x
2
+
2
x
−
120
=
(
x
+
12
)
(
x
−
10
)
So
x
=
−
12
or
x
=
10
Alternatively, complete the square then use the difference of squares identity:
a
2
−
b
2
=
(
a
−
b
)
(
a
+
b
)
as follows:
0
=
x
2
+
2
x
−
120
=
x
2
+
2
x
+
1
−
1
−
120
=
(
x
+
1
)
2
−
121
=
(
x
+
1
)
2
−
11
2
=
(
(
x
+
1
)
−
11
)
(
(
x
+
1
)
+
11
)
=
(
x
−
10
)
(
x
+
12
)
Hence
x
=
10
or
x
=
−
12
Step-by-step explanation:
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Answered by
0
Answer:
x²-2x-120=0
or, x²-12x+10x-120=0
or, x(x-12)+10(x-12)=0
or, (x-12)(x+10)=0
[x(1)-12]= 0
or, x(1)= 12
and, [x(2)+10]=0
or, x(2)= -10
Step-by-step explanation:
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