Question

solve the following quadratic equation. m²-m-16=0​

Answer 1

Answer:

this is the right answer

Answer 2

Answer:

m^2 - m - 16=0

Compare the equation with

am^2 +bm +c=0. We get

a=1, b= - 1 and c= - 16

We know the solution of the equation is

$m = \frac{ - b ± \sqrt{ {b}^{2} - 4ac } }{2a}$

Putting the value of a, b, c we get

$m = \frac{1± \sqrt{1 + 4 \times 16 \times 1} }{2 \times 1}$

So

$m = \frac{1}{2} + \frac{ \sqrt{65} }{2}$

Or

$m = \frac{1}{2} - \frac{ \sqrt{65} }{2}$