Question

Solve the following quadratic equation:

please answer fast!!​

Answer 1

Answer:

Given as x2 – (3√2 + 2i)x + 6√2i =0

x2 – (3√2x + 2ix) + 6√2i = 0

x2 – 3√2x – 2ix + 6√2i = 0

x(x – 3√2) – 2i(x – 3√2) = 0

(x – 3√2) (x – 2i) = 0

(x – 3√2) = 0 or (x – 2i) = 0

x = 3√2 or x = 2i

∴ The roots of the given equation are 3√2, 2i