Question

Solve the following quadratic equation plz fast...
(x/3)+3/(6-x)=2(6+x)/15;x is not equal to 6...reply fast right answer max points awarded...will be marked as brainliest...

Answer 1

$Given: \frac{x}{3} + \frac{3}{6 - x} = \frac{2(6 + x)}{15}$

LCM = 15(6 - x).

$\frac{x}{3} * 15(6 - x) + \frac{3}{6 - x} * 15(6 - x) = \frac{2(6 + x)}{15} * 15(6 - x)$

$5x(6 - x) + 45 = 2(6 + x)(6 - x)$

30x - 5x^2 + 45 = 72 - 2x^2

-3x^2 + 30x + 45 = 72

-3x^2 + 30x - 27 = 0

-3(x^2 - 10x + 9) = 0

x^2 - 10x + 9 = 0

x^2 - 9x - x + 9 = 0

x(x - 9) - 1(x - 9) = 0

(x - 1)(x - 9) = 0

x = 1,9.


Hope this helps!

Answer 2

Hi,

Please see the attached file!!


Thanks