Question

solve the following quadratic equation
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${2x}^{2} - 3x - 1 = 0$

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$\frac{1}{x - 3} - \frac{1}{x + 5} = \frac{1}{6}$
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$\frac{3}{5 - x} + \frac{2}{4 - x} = \frac{8}{x + 2}$
pls help me .....​

Answer 1

1. 2x^2-3x-1=0

a=2,b=-3,c=-1

D=b^2-4ac

=(-3)^2-4×2×(-1)

=9+8

=17

D>0 it has real roots

x=(-b+-under root D)/2a

=(-(-3)+- under root17)/2×2

=(3+- under root 17)/4

x=(3+under root 17)/4, (3-under root 17)/4