Question

Solve the following Quadratic equation:

$= > {x}^{2} - 7x + 12$
​

Answer 1

Answer:

Answer..

$x^2-7x+12$

$x^2-(4+3) x+12$

$x^2-4x-3x+12$

$x(x-4) -3(x-4)$

$(x-3) (x-4)$

x=3 and x=4

Answer 2

Answer:

Hey mate ✌️

Step-by-step explanation:

$= > {x}^{2} - 7x + 12$

→x2 - 7x + 12 = 0

→x2 - 4x - 3x + 12 =0

→x(x - 4) -3(x -4) =0

→(x - 3) (x - 4) =0

Now ,

case 1:

x - 3 =0

→x = 3[Ans]

case 2:

x - 4 =0

→x = 4[Ans]

Hope it helps ❣️❣️