Question

solve the following quadratic equation
${x}^{2} - (2 + i)x - (1 - 7i) = 0$
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Answer 1

Answer:

${x}^{2} - (2 + i)x - (1 - 7i) = 0 \\ ax {}^{2} + bx + c = 0 \\ a = 1 \\ b = - (2 + i) \\ c = - (1 - 7i) \\ then \\ x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac} }{2a}$