Solve the following quadratic equation using factorization method:
3x^2-2√6x+2=0
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Heya..!!!
3x² - 2√6x + 2 = 0
⇒3x² - √6x - √6x + 2 = 0 [ 2×3 = 6 ,√6×√6 = 6 , -√6 - √6 = -2√5 ]
⇒√3x(√3x - √2) - √2(√3x - √2) = 0
⇒(√3x - √2)(√3x - √2)
⇒x = √2/√3 , x = √2/√3
3x² - 2√6x + 2 = 0
⇒3x² - √6x - √6x + 2 = 0 [ 2×3 = 6 ,√6×√6 = 6 , -√6 - √6 = -2√5 ]
⇒√3x(√3x - √2) - √2(√3x - √2) = 0
⇒(√3x - √2)(√3x - √2)
⇒x = √2/√3 , x = √2/√3
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I hope you understand.
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