solve the following quadratic equation x^2+3x+9=0
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x² + 3x + 9 = 0
a = 1 , b = 3 , c = 9
• D = b² - 4ac
= ( 3 ) ² - 4 x 1 x 9
= 9 - 36
= - 27
• x = - b ± √ b² - 4ac / 2
= - 3 ± √ - 27 / 2
= - 3 ± √ 27 x - 1 / 2
( i = √ - 1 )
x = - 3 ± 3√3i / 2 ➡ Answer
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