Question

solve the following quadratic equation x^2-7x+3=0​

Answer 1

This equation has no real roots.

Answer 2

Answer:

x = 6.54 or x = 0.46.

Step-by-step explanation:

We have :

x² - 7x + 3 = 0

Comparing to standard quadratic equation :

ax² + bx + c = 0

We get :

a = 1

b = -7

c = 3

Using sridharacharya formula :

x = -b ± √b² - 4ac/(2a)

We get :

x = 7 ± √(-7)² - 4 × 3 × 1/(2 × 1)

x = 7 ± √49 - 12/(2)

x = 7 ± √37/(2)

x = 7 ± 6.08/(2)

x = 7 + 6.08/2 or x = 7 - 6.08/2

x = 6.54 or x = 0.46.