Question

solve the following quadratic equation(x-4)(x+2)=0​

Answer 1

(x -4)(x +2) = 0

x² + 2x -4x -8 = 0

x² - 2x -8 = 0

factors are already given in question : (x-4) = 0

= x = 4 = α

(x +2) = 0

= x = -2 = β....

α +β = -b/a = 4+(-2) = -2

αβ = c/a = 4 (-2) = -8

hope it help you mate

Answer 2

Answer:

as follows

Step-by-step explanation:

(x-4) (x-2)=0

x²-2x-4x-8 =0

factors are already given in equation :

(x-4)=0

x=4=d

(x+2)=0

x=-2

4+(-2)=-2

4(-2)=-8...

hope this help u out