Question

solve the following quadratic equation x^-7x+3=0 give your answer correct to two decimal places
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I will mark the first answer as brainlyest

Answer 1

$\huge \rm {Answer:-}$

$\bf \red {Given\: Quadratic\: equation:-}$

$\dashrightarrow \tt {x^{2}-7x+3=0}$

★The above given equation is in the form of $\tt {ax^{2}+bx+c=0}$

$\bf \blue {We\: Know:-}$

$\large \dashrightarrow \tt {x=\frac{-b±\sqrt{b^{2}-4ac}}{2a}}$

$\bf \pink {Where,}$

a=1

b= -7

c= 3

★supplanting the values we get,

$\large \dashrightarrow \tt {x=\frac{-(-7)±\sqrt{(7)^{2}-4\times1\times3}}{2\times1}}$

$\large \dashrightarrow \tt {x=\frac{7±\sqrt{49-12}}{2}}$

$\large \dashrightarrow \tt {x=\frac{7±\sqrt{37}}{2}}$

★Considering positive value,

$\large \dashrightarrow \tt {x=\frac{7+\sqrt{37}}{2}}$

$\large \dashrightarrow \tt {x=\frac{7+6.08}{2}}$

$\small \tt {[∵\sqrt{37}=6.08]}$

$\large \dashrightarrow \tt {x=\frac{13.08}{2}}$

$\large \implies \tt \green{\fbox{x=6.54}}$

★ Considering negative value,

$\large \dashrightarrow \tt {x=\frac{7-\sqrt{37}}{2}}$

$\large \dashrightarrow \tt {x=\frac{7-6.08}{2}}$

$\large \dashrightarrow \tt {x=\frac{0.92}{2}}$

$\implies \tt \green{\fbox{x=0.46}}$

$\bf \purple {Thereupon,}$

★The value of x can be 6.54 or 0.46 respectively.