solve the following quadratic equation x2-11x-80=0
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X² _11X _80 =0
USING QUADRATIC FORMULA
D= b² _ 4ac
D = (_11)² _ 4×1×-80
D = 121 + 320
D= 441.
441>0
REAL UNEQUAL ROOTS EXIST
X = - b+ROOT D/ 2A
OR
X = -b _ ROOT D / 2A
X = 11 + ROOT 441/ 2×1 => X = 11 + 21 /2
=> 32 /2 =>16
OR
X = 11 _ ROOT 441 /2×1=> 11_21/2
=>-10 /2 = 5
THEREFORE 5 AND 16 ARE THE 2 ROOTS
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