Math, asked by sardarchouhan15, 8 months ago

solve the following quadratic equation x2-11x-80=0​

Answers

Answered by Anonymous
4

X² _11X _80 =0

USING QUADRATIC FORMULA

D= b² _ 4ac

D = (_11)² _ 4×1×-80

D = 121 + 320

D= 441.

441>0

REAL UNEQUAL ROOTS EXIST

X = - b+ROOT D/ 2A

OR

X = -b _ ROOT D / 2A

X = 11 + ROOT 441/ 2×1 => X = 11 + 21 /2

=> 32 /2 =>16

OR

X = 11 _ ROOT 441 /2×1=> 11_21/2

=>-10 /2 = 5

THEREFORE 5 AND 16 ARE THE 2 ROOTS

Answered by mskhushi701
2

Step-by-step explanation:

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