solve the following quadratic equation x2-4x+13=0
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Answer:
x² - 4x + 13 = x² - 4x + 4 + 9
= (x - 2)² - 9i²
= (x - 2)² - (3i)²
= (x - 2 - 3i)(x - 2 + 3i)
the zeroes of x² - 4x + 13 are 2 + 3i and 2 - 3i.
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