Question

Solve the following quadratic equation: (x²-4x+9)²-8(x²-4x+9)+15=0​

Answer 1

Answer:

x

2

−5x+6=0=(x−2)(x−3)

Roots are 2 and 3

For x

2

−8x+15=0=(x−5)(x−3)

Roots are 3 and 5

We have common root =3

We know that common root is the root of x

2

+4x+q=0

Putting x=3 we get 9+12+q=0

⇒q=−21