Solve the following quadratic equation: (x²-4x+9)²-8(x²-4x+9)+15=0
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Answer:
x
2
−5x+6=0=(x−2)(x−3)
Roots are 2 and 3
For x
2
−8x+15=0=(x−5)(x−3)
Roots are 3 and 5
We have common root =3
We know that common root is the root of x
2
+4x+q=0
Putting x=3 we get 9+12+q=0
⇒q=−21
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